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make release: Don't print the release message on stdout.

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It's just too long for copy/paste, so just let the user know the name
of the file containing the message instead.
This commit is contained in:
Carl Worth 2010-04-16 08:33:31 -07:00
parent ff13111cf3
commit 4906f6b9ae
1 changed files with 1 additions and 4 deletions
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5
Makefile.local
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@ -79,11 +79,8 @@ release: verify-no-dirty-code
mv $(TAR_FILE) $(SHA1_FILE) $(GPG_FILE) releases mv $(TAR_FILE) $(SHA1_FILE) $(GPG_FILE) releases
git tag -s -m "$(PACKAGE) $(VERSION) release" $(VERSION) git tag -s -m "$(PACKAGE) $(VERSION) release" $(VERSION)
git push origin $(VERSION) git push origin $(VERSION)
@echo "Please send a release announcement as follows:"
@echo ""
$(MAKE) release-message
$(MAKE) release-message > $(PACKAGE)-$(VERSION).announce $(MAKE) release-message > $(PACKAGE)-$(VERSION).announce
@echo "(This message is also available in $(PACKAGE)-$(VERSION).announce" @echo "Please send a release announcement using $(PACKAGE)-$(VERSION).announce as a template."
.PHONY: release-message .PHONY: release-message
release-message: release-message: